Algebraeasy · Past Paper
The nature of roots of 9x^2 - 6x + 1 = 0 is:
AReal and equal
BReal and unequal
CImaginary
DIrrational
✓ Correct Answer: A — Real and equal
D = (-6)^2 - 4(9)(1) = 36 - 36 = 0.
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✓ Correct Answer: A — Real and equal
D = (-6)^2 - 4(9)(1) = 36 - 36 = 0.
Share this question