Algebrahard · Past Paper
Solve for x: 2^(2x) - 10 ⋅ 2^x + 16 = 0.
A1, 3
B2, 3
C1, 2
D0, 4
✓ Correct Answer: A — 1, 3
Let 2^x = y. y^2 - 10y + 16 = 0 → (y-2)(y-8) = 0. 2^x=2 → x=1; 2^x=8 → x=3.
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✓ Correct Answer: A — 1, 3
Let 2^x = y. y^2 - 10y + 16 = 0 → (y-2)(y-8) = 0. 2^x=2 → x=1; 2^x=8 → x=3.
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