Algebrahard · Past Paper
If the sum of the roots of 3x^2 + (2k+1)x - (k+5) = 0 is equal to their product, find k.
A4
B2
C-2
D1
✓ Correct Answer: A — 4
Sum = -(2k+1)/3, Product = -(k+5)/3. Set them equal: 2k+1 = k+5 => k = 4.
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✓ Correct Answer: A — 4
Sum = -(2k+1)/3, Product = -(k+5)/3. Set them equal: 2k+1 = k+5 => k = 4.
Share this question