Algebramedium · Past Paper
If the roots of x^2 + px + 12 = 0 are in the ratio 1:3, find p.
A±8
B±4
C±6
D±12
✓ Correct Answer: A — ±8
Roots k, 3k. Product 3k^2 = 12 → k^2 = 4 → k = ±2. Sum 4k = -p → p = -4(±2) = ±8.
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✓ Correct Answer: A — ±8
Roots k, 3k. Product 3k^2 = 12 → k^2 = 4 → k = ±2. Sum 4k = -p → p = -4(±2) = ±8.
Share this question