Algebrahard · Past Paper
If the roots of x^2 - bx + c = 0 differ by 1, then:
Ab^2 = 4c + 1
Bb^2 = 4c - 1
Cb = 4c + 1
Dc^2 = 4b + 1
✓ Correct Answer: A — b^2 = 4c + 1
(α-β)^2 = 1 => (α+β)^2 - 4αβ = 1 => b^2 - 4c = 1 => b^2 = 4c + 1.
Share this question
More from Algebra
- A number decreased by 10 is 5. What is the number?
- What are the factors of x^2 - 12x + 36?
- If P(x) is a polynomial of degree 4, and it is divided by a polynomial of degree 2, what is the degree of the quotient?
- The sum of the squares of two consecutive odd numbers is 290. Find the numbers.
- If the roots of (k-1)x^2 - 10x + 3 = 0 are reciprocal, find k.