If the roots of (b-c)x^2 + (c-a)x + (a-b) = 0 are equal... – Algebra

Algebrahard · Past Paper

If the roots of (b-c)x^2 + (c-a)x + (a-b) = 0 are equal, find the relation between a, b, c.

A2b = a+c

Bb = a+c

C2a = b+c

Da = b+c

✓ Correct Answer: A — 2b = a+c

Sum of coefficients is 0, so one root is 1. Since roots are equal, both are 1. Product (a-b)/(b-c) = 1 → a-b = b-c → 2b = a+c.

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