Algebraeasy · Past Paper
If roots are 2 and -3, the quadratic equation is:
Ax^2 + x - 6 = 0
Bx^2 - x - 6 = 0
Cx^2 + x + 6 = 0
Dx^2 - 5x + 6 = 0
✓ Correct Answer: A — x^2 + x - 6 = 0
Using (x - r1)(x - r2) = 0, we get (x - 2)(x + 3) = x^2 + x - 6 = 0.
Share this question