Algebrahard · Past Paper
If α, β are roots of x^2 - 2x + 4 = 0, find α^3 + β^3.
A-16
B16
C8
D-8
✓ Correct Answer: A — -16
α+β=2, αβ=4. α^3+β^3 = (2)^3 - 3(4)(2) = 8 - 24 = -16.
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✓ Correct Answer: A — -16
α+β=2, αβ=4. α^3+β^3 = (2)^3 - 3(4)(2) = 8 - 24 = -16.
Share this question