Algebrahard · Past Paper
If α, β are roots of 2x^2 - 6x + 3 = 0, find α^3 + β^3.
A27/2
B9
C81/4
D27/4
✓ Correct Answer: A — 27/2
α+β=3, αβ=3/2. α^3+β^3 = (α+β)^3 - 3αβ(α+β) = 27 - 3(3/2)(3) = 27 - 27/2 = 27/2.
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✓ Correct Answer: A — 27/2
α+β=3, αβ=3/2. α^3+β^3 = (α+β)^3 - 3αβ(α+β) = 27 - 3(3/2)(3) = 27 - 27/2 = 27/2.
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