Algebramedium · Past Paper
If 4 is a root of x^2 - px + 12 = 0, what is the value of p?
A7
B-7
C8
D13
✓ Correct Answer: A — 7
4^2 - p(4) + 12 = 0 → 16 - 4p + 12 = 0 → 28 = 4p → p = 7.
Share this question
✓ Correct Answer: A — 7
4^2 - p(4) + 12 = 0 → 16 - 4p + 12 = 0 → 28 = 4p → p = 7.
Share this question