Algebraeasy · Past Paper
For what value of m is x^2 - mx + 1 = 0 a perfect square?
A1
B±2
C0
D4
✓ Correct Answer: B — ±2
D must be 0 for a perfect square. m^2 - 4(1)(1) = 0 → m^2 = 4 → m = ±2.
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✓ Correct Answer: B — ±2
D must be 0 for a perfect square. m^2 - 4(1)(1) = 0 → m^2 = 4 → m = ±2.
Share this question