Algebrahard · Past Paper
For the equation x^2 + x + 1 = 0, α^3 + β^3 is:
A2
B1
C-2
D0
✓ Correct Answer: A — 2
α^3 + β^3 = (α+β)(α^2-αβ+β^2) = (-1)((α+β)^2-3αβ) = (-1)(1-3) = 2.
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✓ Correct Answer: A — 2
α^3 + β^3 = (α+β)(α^2-αβ+β^2) = (-1)((α+β)^2-3αβ) = (-1)(1-3) = 2.
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