Algebramedium · Past Paper
Find the quadratic equation whose roots are -3 and 4.
Ax^2 - x - 12 = 0
Bx^2 + x - 12 = 0
Cx^2 - 7x + 12 = 0
Dx^2 + 7x + 12 = 0
✓ Correct Answer: A — x^2 - x - 12 = 0
Sum = -3+4=1, Product = -3*4=-12. Equation: x^2 - (1)x + (-12) = 0.
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