Algebrahard · Past Paper
Find 'k' for which the equation x^2 + 2(k+1)x + k^2 = 0 has equal roots.
A-1/2
B1/2
C1
D-1
✓ Correct Answer: A — -1/2
D = [2(k+1)]^2 - 4(k^2) = 0 => 4(k^2+2k+1) - 4k^2 = 0 => 8k + 4 = 0 => k = -1/2.
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✓ Correct Answer: A — -1/2
D = [2(k+1)]^2 - 4(k^2) = 0 => 4(k^2+2k+1) - 4k^2 = 0 => 8k + 4 = 0 => k = -1/2.
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