Algebrahard · Past Paper
What is the sum of coefficients in (x-y)^2?
A0
B1
C2
D-2
✓ Correct Answer: A — 0
(x-y)^2 = 1x^2 - 2xy + 1y^2. Sum: 1 - 2 + 1 = 0. Or simply set x=1, y=1.
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✓ Correct Answer: A — 0
(x-y)^2 = 1x^2 - 2xy + 1y^2. Sum: 1 - 2 + 1 = 0. Or simply set x=1, y=1.
Share this question