Algebrahard · Past Paper
Find the value of (x-a)^3 + (x-b)^3 + (x-c)^3 if a+b+c = 3x.
A3(x-a)(x-b)(x-c)
B0
Cx^3 - abc
D3abc
✓ Correct Answer: A — 3(x-a)(x-b)(x-c)
If A+B+C=0, then A^3+B^3+C^3 = 3ABC. Here (x-a)+(x-b)+(x-c) = 3x - (a+b+c) = 3x - 3x = 0.
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