Algebramedium · Past Paper
Find the LCM of x^2 - 1 and x^2 - 2x + 1.
A(x-1)(x+1)
B(x-1)^2(x+1)
C(x-1)(x+1)^2
D(x^2-1)^2
✓ Correct Answer: B — (x-1)^2(x+1)
x^2-1 = (x-1)(x+1) and x^2-2x+1 = (x-1)^2. LCM is (x-1)^2(x+1).
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✓ Correct Answer: B — (x-1)^2(x+1)
x^2-1 = (x-1)(x+1) and x^2-2x+1 = (x-1)^2. LCM is (x-1)^2(x+1).
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