Algebramedium · Past Paper

Find HCF of 2x^2 - 8 and x^2 - 4x + 4.

Ax - 2
B2(x - 2)
C(x - 2)^2
Dx + 2

✓ Correct Answer: Ax - 2

2(x^2-4) = 2(x-2)(x+2) and (x-2)^2. Common factor is (x-2).

Share this question

More from Algebra