Algebrahard · Past Paper
Solve for x and y: 2/(3x+2y) + 3/(3x-2y) = 17/5 and 5/(3x+2y) + 1/(3x-2y) = 2.
Ax=1, y=1/2
Bx=1/2, y=1
Cx=1, y=1
Dx=2, y=1
✓ Correct Answer: A — x=1, y=1/2
Let u=1/(3x+2y), v=1/(3x-2y). 2u+3v=17/5, 5u+v=2. Solving gives u=1/5, v=1. 3x+2y=5, 3x-2y=1. Adding: 6x=6 -> x=1. Subtracting: 4y=4 -> y=1.
Share this question
More from Algebra
- The degree of the product (x^2 + 1)(x^3 - x + 1)(x + 5) is:
- If the discriminant is a perfect square, the roots are:
- Find the remainder when x^4 + x^3 + x^2 + x + 1 is divided by x.
- Find the x-intercept of the line 3x - 4y = 12.
- The cost of 2 pencils and 3 pens is Rs 40. The cost of 3 pencils and 2 pens is Rs 35. Find the cost of a pencil.