Algebrahard · Past Paper
Five years ago, A's age was 3 times B's age. Ten years later, A will be twice as old as B. Find current age of A.
A50
B45
C35
D40
✓ Correct Answer: A — 50
A-5=3(B-5) -> A-3B=-10. A+10=2(B+10) -> A-2B=10. Subtracting gives -B = -20 (B=20). A=50.
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