Algebrahard · Past Paper
Five years ago, a father's age was 7 times his son's age. Five years hence, the father's age will be 3 times his son's age. Find the father's present age.
A40 years
B35 years
C45 years
D50 years
✓ Correct Answer: A — 40 years
(F-5)=7(S-5) and (F+5)=3(S+5). Solving these equations gives F=40, S=10.
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