Algebrahard · Past Paper
Find the value of k for which the system kx - y = 2 and 6x - 2y = 3 has a unique solution.
Ak != 3
Bk = 3
Ck = 0
Dk != 0
✓ Correct Answer: A — k != 3
Unique solution if a1/a2 != b1/b2. k/6 != -1/-2 -> k/6 != 1/2 -> k != 3.
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