Algebramedium · Past Paper
What are the factors of x^3 - 8?
A(x-2)(x^2+2x+4)
B(x-2)(x^2-2x+4)
C(x+2)(x^2-2x+4)
D(x-2)^3
✓ Correct Answer: A — (x-2)(x^2+2x+4)
Difference of cubes: a^3 - b^3 = (a-b)(a^2+ab+b^2). Here x^3 - 2^3.
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✓ Correct Answer: A — (x-2)(x^2+2x+4)
Difference of cubes: a^3 - b^3 = (a-b)(a^2+ab+b^2). Here x^3 - 2^3.
Share this question