Algebramedium · Past Paper
What are the factors of 1 - 64x^3?
A(1-4x)(1+4x+16x^2)
B(1+4x)(1-4x+16x^2)
C(1-4x)^3
D(1-8x)(1+8x+64x^2)
✓ Correct Answer: A — (1-4x)(1+4x+16x^2)
1^3 - (4x)^3 is a difference of cubes.
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