Algebrahard · Past Paper
Factorize: (x^2-5x+6)(x^2-5x+4) - 24
Ax(x-5)(x^2-5x+10)
B(x-2)(x-3)(x-1)(x-4)
C(x^2-5x)(x^2-5x+10)
Dx(x-5)(x-2)(x-3)
✓ Correct Answer: A — x(x-5)(x^2-5x+10)
Let y = x^2-5x. Expression is (y+6)(y+4)-24 = y^2+10y+24-24 = y^2+10y = y(y+10) = (x^2-5x)(x^2-5x+10) = x(x-5)(x^2-5x+10).
Share this question
More from Algebra
- If 4x - 1 = 7, find the value of 2x.
- If α and β are roots of x^2 + bx + c = 0, then α^2 + β^2 is:
- If the roots of (a^2+b^2)x^2 - 2b(a+c)x + (b^2+c^2) = 0 are equal, then a, b, c are in:
- The perimeter of a rectangle is 24 cm. If the length is 2 cm more than the width, find the width.
- If 2x + 5 = 5x - 4, what is x?