Algebrahard · Past Paper

Factorize: (x^2-5x+6)(x^2-5x+4) - 24

Ax(x-5)(x^2-5x+10)
B(x-2)(x-3)(x-1)(x-4)
C(x^2-5x)(x^2-5x+10)
Dx(x-5)(x-2)(x-3)

✓ Correct Answer: Ax(x-5)(x^2-5x+10)

Let y = x^2-5x. Expression is (y+6)(y+4)-24 = y^2+10y+24-24 = y^2+10y = y(y+10) = (x^2-5x)(x^2-5x+10) = x(x-5)(x^2-5x+10).

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