Algebramedium · Past Paper
Factorize: a^3 + 27
A(a+3)(a^2-3a+9)
B(a-3)(a^2+3a+9)
C(a+3)^3
D(a+3)(a^2+3a+9)
✓ Correct Answer: A — (a+3)(a^2-3a+9)
Sum of cubes: a^3 + b^3 = (a+b)(a^2-ab+b^2). Here a^3 + 3^3.
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✓ Correct Answer: A — (a+3)(a^2-3a+9)
Sum of cubes: a^3 + b^3 = (a+b)(a^2-ab+b^2). Here a^3 + 3^3.
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